The electric potential at any point as a function of distance $(x)$ in meter is given by $V = 5x^2 + 10x -9 \,(volt)$ Value of electric field at $x = 1$ is......$Vm^{-1}$
$-20$
$6$
$11$
$-23$
If on the $x$-axis electric potential decreases uniformly from $60 \,V$ to $20 \,V$ between $x=-2 \,m$ to $x=+2 \,m$, then the magnitude of electric field at the origin
Electric potential is given by
$V = 6x - 8x{y^2} - 8y + 6yz - 4{z^2}$
Then electric force acting on $2\,C$ point charge placed on origin will be......$N$
The electric potential in a region is represented as $V = 2x + 3y -z$ ; then the expression of electric field strength is
Two parallel plates separated by a distance of $5\,mm$ are kept at a potential difference of $50\,V.$ A particle of mass ${10^{ - 15}}\,kg$ and charge ${10^{ - 11}}\,C$ enters in it with a velocity ${10^7}\,m/s.$ The acceleration of the particle will be
The electric potential $V(x)$ in a region around the origin is given by $V(x) = 4x^2\,volts$ . The electric charge enclosed in a cube of $1\,m$ side with its centre at the origin is (in coulomb)